Question

What is the equation of a line, in point-slope form, that passes through (−2, −6)(−2, −6) and has a slope of 1313 ?

a.y−2=13(x−6)y−2=13(x−6)

b.y 2=13(x 6)y 2=13(x 6)
 
c. y−6=13(x−2)y−6=13(x−2)
 
d. y 6=13(x 2)

Answer 1

the equation of a line that passes throught (x1,y1) and the slope is m is
y-y1=m(x-x1)

given
point is (-2,-6) and slope is 13
y-(-6)=13(x-(-2))
y+6=13(x+2)

last one
seems that nobody can type a "+" sign on this site

D is the answer

Answer 2

Answer: d.
`y+6=13(x+2)`

Explanation:

The equation of a line passing through point (a,b) and having slope 'm' is given by :-

`(y-b)=m(x-a)`

Given : Point = (-2,-6) and Slope = 13

Now, the equation of a line, in point-slope form, that passes through (-2, -6) and has a slope of 13 will be :-

`(y-(-6))=13(x-(-2))\\\\\Rightarrow\ y+6=13(x+2)`

Hence, the equation of a line, in point-slope form, that passes through (-2, -6) and has a slope of 13 =
`y+6=13(x+2)`