139,904 views
19 votes
19 votes
In a sampling taken at the local factory, three (3) out of every 100 CD players were defective. Based on the sample, approximately how many CD players may be defective in a shipment of 1920 CD players? Write a proportion that could be used to solve the problem, and then state the answer.

User Tompave
by
2.4k points

1 Answer

12 votes
12 votes

Answer:

58 CD players

Step-by-step explanation:

Three (3) out of every 100 CD players were defective.


\frac{\text{Defective}}{\text{Total}}=(3)/(100)

If there is a shipment of 1920 CD players, we have:


\frac{\text{Defective}}{\text{Total}}=\frac{\text{Defective}}{1920}

The proportion that could be used is:


(3)/(100)=(Defective)/(1920)

We solve the proportion above for the number of defective CD players.


\begin{gathered} \text{Defective}*100=1920*3 \\ \text{Defective=}(1920*3)/(100) \\ =57.6 \\ \approx58 \end{gathered}

Therefore, approximately 58 CD players may be defective in a shipment of 1920 CD players.

User Johnathan Barclay
by
2.7k points