Answer:
Answer:
x=-2, x=1, x=3
Explanation:
Step-by-step explanation:
one zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function
the following polynomials have the function
f(x)=x^3-2x^2-5x+6
note 2 is not a zero of the function
but x=-2
to find the other zeros we say
f(x)/x+2=x^3-2x^2-5x+6/(x+2)
we have the quadratic equation
x^2-4x+3
factorizing the above, using factorization method
(x^2-3x-x+3)
(x^2-3x)(-x+3)
x(x-3)-1(x-3)
(x-1)(x-3)
x=1, x=3
the zeros of the function are
x=-2, x=1,x=3
substituting the values back into the function
we have zero
f(1)=1^3-2(1)^2-5(1)+6
F(1)=0