Answer: A. 210
Explanation:
We know that the number of combinations of n things taking r at time is given by expression :-
(1)
The given expression :
which basically gives the number of combinations of 10 things taking 6 at a time.
Using (1) , we have
![^(10)C_(6)=(10!)/(6!(10-6)!)\\\\=(10*9*8*7*6!)/(6!4!)\\\\=(10*9*8*7)/(4!)\ \ [\text{Cancel }6!\text{ from numerator and denominator}]\\\\=(10*9*8*7)/(4*3*2*1)\\\\=210](https://img.qammunity.org/2017/formulas/mathematics/high-school/sj9fa1gidqnx3mhtnaqhx0vxu3jdrwq1ra.png)
Hence, the correct answer is A. 210 .