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Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18. The system that represents Mira’s numbers is below. x – y = 4 x + y = 18 Which two numbers did Mira pick? (10, 8) (18, 4) (20, 16) (40, 32)

User Ezra
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2 Answers

1 vote
(20, 16), they are the only two numbers that have a difference of 4 and take half of each of those numbers and add them together it will equal 18.

Hope this helped :)
User Rethunk
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7.7k points
5 votes

Answer: The correct option is (C) (20, 16).

Step-by-step explanation: Given that Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18.

We are to find the two numbers that Mira pick.

Let a and b be the two numbers that Mira pick.

Then, according to the given information, we have


x-y=4~~~~~~~~~~~~~~~~~~~~~~(i)\\\\(1)/(2)(x+y)=18~~~~~~~~~~~~~~~~(ii)

From equation (i), we have


x-y=4\\\\\Rightarrow x=y+4~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

Substituting the value of x from equation (iii) in equation (ii), we get


(1)/(2)(x+y)=18\\\\\Rightarrow x+y=36\\\\\Rightarrow y+4+y=36\\\\\Rightarrow 2y=32\\\\\Rightarrow y=(32)/(2)\\\\\Rightarrow y=16.

Now, from equation (iii), we get


x=y+4=16+4=20.

Thus, the two numbers that Mira pick are 20 and 16.

Option (C) is CORRECT.

User Rutwick Gangurde
by
8.5k points
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