assuming this a system of equations and you need the solution set, you can solve it by elimination or substitution--whichever you find easier. i'll use elimination:
2x - 5y = 3
x - 3y = 1
here, it'll be pretty easy to get your x values to match so you can cancel them out. just multiply your bottom equation by 2, then subtract:
2x - 5y = 3
- (2x - 6y = 2)
your 2x's cancel out and -5y + 6y is simply y, so you're left with:
y = 1
that already gives you your answer, because you can see that the first ordered pair is the only pair with a y-value that's 1, but still, to check your x-value, you just plug your y-value into one of the equations:
x - 3(1) = 1
x - 3 = 1
x = 4
so your solution is (4, 1).