Question

A star has a surface area of 6.89x1018 m2. How much power does it radiate if it has a surface temperature of 7,701 K? Submit your answer in exponential form.

Answer 1

1.37 * 10^ 27 watts

Step-by-step explanation:

The power radiated by a body with surface temperature T and surface area A is given by

`P=\sigma AT^4`

where σ = 5.67 x 10^-8 watt / m^2 K^4.

Now in our case

A = 6.89 x 10^18 m^2 and T = 7701.

Therefore,

`P=5.67*10^(-8)*6.89\cdot10^(18)*7701^4`

which we evaluate to get

`\boxed{P=1.37*10^(27)W.}`

Hence, the power radiated by the star is 1.37 x 10^27 watts.