Question

Factorise tis please.

`(x+3)^(2) +2(x+3)`

Answer 1

`\displaystyle \boxed{(a+b)=a^2+2ab+b^2} \\ \\ (x+3)^2+2(x+3)= \\ x^2+2 \cdot x \cdot 3 +3^2+2x+6 = \\ x^2+6x+9+2x+6= \\ x^2+8x+15= \\ \\ \Delta= b^2-4ac \\ \Delta=8^2-4 \cdot1 \cdot15 \\ \Delta=64-60=4 \\ \\ \\ X_(1,2)= (-b\pm √(\Delta) )/(2a) = (-8\pm2)/(2) = \\ \\X1=5 \\ X2=3`