Question

What are the solutions of 3x2 + 14x + 16 = 0?

x = , –2
x = –2,
x = , 2
x = , 2

Answer 1

Assume you mean 3x^2 when you typed the question.

3x^2+14x+16=0
(3x+8)(x+2)=0

x=-8/3 or -2

Answer 2

option (A) is correct.

x = -2

Explanation:

Given : equation
`3x^2+14x+16=0`

We have to solve for x,

Consider the given equation
`3x^2+14x+16=0`

we will solve the given quadratic equation using middle term split method, we have,

14x can be writen as 6x + 8x , we have,

`3x^2+14x+16=0 \Rightarrow 3x^2+6x+8x+16=0`

Taking 3x common from frst two terms and 8 common from lasttwo term , we have,

`\Rightarrow 3x(x+2)+8(x+2)=0`

Taking (x + 2) common, we have,

`\Rightarrow (x+2)(3x+8)=0`

Thus, Apply zero product rule,
`a\cdot b=0 \Rightarrow a =0 \ or\ b= 0`

`\Rightarrow (x+2)=0` or
`\Rightarrow (3x+8)=0`

`\Rightarrow x=-2` or
`\Rightarrow x=(-8)/(3)`

Thus, option (A) is correct.