Register

Given: 2x-3y+z=0 3x+2y=35 4y-2z=14 Which of the following is a solution to the given system? (2, 3, 5) (3, 2, 0) (1, 16, 0) (7, 7, 7)

Given: 2x-3y+z=0 3x+2y=35 4y-2z=14 Which of the following is a solution to the given system? (2, 3, 5) (3, 2, 0) (1, 16, 0) (7, 7, 7)
125k views
3 votes
Given:

2x-3y+z=0

3x+2y=35

4y-2z=14

Which of the following is a solution to the given system?

(2, 3, 5)

(3, 2, 0)

(1, 16, 0)

(7, 7, 7)

User Mete
by
7.8k points

2 Answers

1 vote

Answer:

the answer is (7, 7, 7)

Explanation:


User Naaff
by
8.0k points
6 votes
If x and y are either 2 or 3 it would not fit 3x+2y=35.
so the first two solutions are out.
Try the third one 16*4 is 64. 64-0 is not 14 so the third one is out too.

The answer is (7,7,7)
User Tocker
by
8.4k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!