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Given: 2x-3y+z=0 3x+2y=35 4y-2z=14 Which of the following is a solution to the given system? (2, 3, 5) (3, 2, 0) (1, 16, 0) (7, 7, 7)
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3 votes
Given:

2x-3y+z=0

3x+2y=35

4y-2z=14

Which of the following is a solution to the given system?

(2, 3, 5)

(3, 2, 0)

(1, 16, 0)

(7, 7, 7)

User Mete
by
7.3k points

2 Answers

1 vote

Answer:

the answer is (7, 7, 7)

Explanation:


User Naaff
by
7.6k points
6 votes
If x and y are either 2 or 3 it would not fit 3x+2y=35.
so the first two solutions are out.
Try the third one 16*4 is 64. 64-0 is not 14 so the third one is out too.

The answer is (7,7,7)
User Tocker
by
8.0k points
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