Question

How do I solve log(3x + 2) = 3?

Answer 1

If we solve the equation
`log(3x+2)=3` we get that
`x=332.67`.

Explanation:

We have to remember that the logarithm is the inverse operation to exponentiation, so we have that:

`c=log_(b)\ a\ \Longrightarrow\ a=b^(c)`

If the base
`b` doesn't appear explicitly it means that the logarithm is in base 10.

Going back to our equation we have that:

`3=log_(10)(3x+2)\ \Longrightarrow\ (3x+2)=10^(3)`

`3x+2=1000`

`3x=998`

`x=332.67`