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a 155 gram sample of copper was heated to 150.0ºC then placed into 250 gram of water at 19.8ºC. (The specific heat of copper is 0.385J/gºC.)Calculate the final temperature of the mixture. (assume no heat loss to the surroundings)

1 Answer

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Final temp will be averages of the copper and the water. Since no energy values are discussed, specific heat will be irrelevant here.

150.0ºC+19.8ºC=169.8ºC/2=84.9ºC
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