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Guys i need help with checking my work for the elimination. i got y=4 , x=1. equation : 3x-2y=5 and 6x-4y=-10. how do i substitute the value for x and y in this equation to chec…
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Guys i need help with checking my work for the elimination. i got y=4 , x=1. equation : 3x-2y=5 and 6x-4y=-10. how do i substitute the value for x and y in this equation to chec…
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Aug 10, 2017
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guys i need help with checking my work for the elimination. i got y=4 , x=1. equation : 3x-2y=5 and 6x-4y=-10. how do i substitute the value for x and y in this equation to check if my answer is correct or wrong. show your work.
Mathematics
high-school
Lokesh SN
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Lokesh SN
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3(1) - 2(4) = 5
3 - 8 =5
-5 = 5 < your answers are incorrect because -5 is not equal to a positive 5.
try doing it this way:
so your equations are
3x - 2y = 5 and
6x - 4y = -10
multiply the first equation by 2 so it becomes
6x + 4y = 10
then you add the two equations
6x + 4y = 10
6x - 4y = -10
------------------
12x = 0
x = 0
then you plug 0 into any one of the previous equations that we started off with
I will use: 3x - 2y = 5
3(0) - 2y = 5
0 - 2y = 5
-2y = 5 - 0
y = 5/-2 or -2 1/2
you can check by adding the x value = 0 and the y value = -5/2 into any one of the previous equations
I will use: 6x - 4y = -10
6(0) - 4(-5/2) = -10
0 - (20/2) = -10
-20/2 = -10
-10 = -10
hope this helps :)
Binji
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Aug 14, 2017
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Binji
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