Register

17. GRAVITY The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6 + 96t - 16t2 feet, where t is the time in seconds.…

17. GRAVITY The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6 + 96t - 16t2 feet, where t is the time in seconds.…
218k views
4 votes
17. GRAVITY The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6 + 96t - 16t2 feet, where t is the time in seconds. According to this model, how high is the ball after 7 seconds? Explain.

User Maloomeister
by
7.8k points

1 Answer

2 votes
76.23 it would be because 6 + 9060 -62 feet and it says how many seconds that's how I know what it is
User Ldavid
by
8.6k points
← Prev Question Next Question →

Related questions

User Cperez
asked Oct 22, 2024 150k views
Complete the square to write 16t2 - 96t+48 = 0 as DONE DEUENDO C 9 of 9
Cperez asked Oct 22, 2024
by Cperez
7.4k points
1 answer
3 votes
150k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!