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What is the volume of a cylinder with a height of 18.6 in and a base with a radius of 6.2 in, to the nearest tenth of a cubic inch?

User StefanGordon
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1 Answer

18 votes
18 votes

Solution:

Concept:

The volume of a cylinder is given below as


\begin{gathered} V_{\text{cylinder}}=\pi* r^2* h \\ \text{Where,} \\ r=6.2in \\ h=18.6in \end{gathered}

By substituting the values in the question, we will have


\begin{gathered} V_{\text{cylinder}}=\pi* r^2* h \\ V_{\text{cylinder}}=\pi*6.2^2*18.6 \\ V_{\text{cylinder}}=2246.188in^3 \\ V_{\text{cylinder}}\approx(nearest\text{ tenth)} \\ V_{\text{cylinder}}=2248.2in^3 \end{gathered}

Hence,

The volume of the cylinder is = 2246.2 in³

User Mksuth
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