Express log2 6 + log2 7 as a single logarithm. PLEASEE HELP! A. log2 7/6 B. log2 6/7 C. log2 √ 42 D. log2 42

Question

asked May 25, 2017 215k views

1 Answer

Lunedor · Answer 1 · 2017-05-30T20:14:17+0000

Answer: The correct option is (D)
$\log_242.$

Step-by-step explanation: We are given to write the following logarithmic expression as a single logarithm :

$E=\log_26+\log_27.$

We will be using the following property of logarithm :

$\log_ab+\log_ac=\log_abc.$

For the given expression, we have

$E\\\\=\log_26+\log_27\\\\=\log_2(6*7)\\\\=\log_242.$

Thus, the required single logarithm is
$\log_242.$

Option (D) is CORRECT.