In a quadratic equation , we use the quadratic formula to find the solutions x = (-b ± √(b2 - 4ac)) / 2a where a, b, and c are coefficients of the equation ax2 + bx + c = 0 Since x=6 is the only x-intercept, the equation would be (x - 6)(x - 6) = 0 Expanding this out, we get x2 - 12x + 36 = 0 In this equation, a = 1b = -12c = 36 Now the discriminant is the square-root part of the formula: b2 - 4ac Now plug in the values of a,b, and c into the discriminant. (-12)2 - 4(1)(36) = 144 - 144 = 0 This number is under the square-root. The square-root of 0 is 0. Your answer is (A).
(I had the same question in math last week)