Question

What are equivalent expressions for 6(y-1) and 64x+80

Answer 1

To find equivalent expressions, distribute the first one and factor the second one.


`6(y-1) \\ (6*y)+(6*-1) \\ 6y-6 \\ \\ 6(y-1)=6y-6 \\ \\ 64x+80 \\ 16( (64)/(16)x+ (80)/(16)) \\ 16(4x+5) \\ \\ 64x+80=16(4x+5)`