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What are equivalent expressions for 6(y-1) and 64x+80

User Pashute
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1 Answer

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To find equivalent expressions, distribute the first one and factor the second one.


6(y-1) \\ (6*y)+(6*-1) \\ 6y-6 \\ \\ 6(y-1)=6y-6 \\ \\ 64x+80 \\ 16( (64)/(16)x+ (80)/(16)) \\ 16(4x+5) \\ \\ 64x+80=16(4x+5)
User Kianenigma
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