Question

a 0.65 kg ball is moving in a circular path which has a radius of 1.35 meters with a linear speed of 4.5m/s. what is the centriperal force acting on this ball

Answer 1

The acceleration formula is

`a_(c)=(v^(2))/(r)`

We are given

`v=4.5\ m/s`

`r=1.35\ m`
Plug in:

`a_(c)=((4.5\ m/s)^(2))/(1.35\ m)=15\ m/s^(2)`

The formula for force is

`F=ma`

We now have

`a=15\ m/s^(2)`

`m=0.65\ kg`
Plug in:

`F=15\ m/s^(2)*0.65\ kg=9.75\ N`

So the centripetal force is 9.75 Newtons.