menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question
a number a is a root of p(x) if and only if the reminder, when dividing the polynomial by x + a, equals zero, true or false?
asked
Apr 28, 2017
133k
views
1
vote
a number a is a root of p(x) if and only if the reminder, when dividing the polynomial by x + a, equals zero, true or false?
Mathematics
high-school
Ozarov
asked
by
Ozarov
8.3k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
2
Answers
4
votes
True! You can tell because (x - a) is what we can assume to be a factor...if you solve for a: x - a = 0 + a on both sides x = a that is your root. So it will always be the opposite of the number in the parentheses of the factor. You can't always assume something is a factor, but here you can b/c you're looking for a root.
Thordarson
answered
Apr 29, 2017
by
Thordarson
8.4k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
5
votes
False
, it's only true when the polynomial is being divided by x - a.
Oginga Michael
answered
May 3, 2017
by
Oginga Michael
7.9k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
← Prev Question
Next Question →
No related questions found
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
9.5m
questions
12.2m
answers
Other Questions
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org