Question

Let d = 19 inches, h = 21 inches. Find the:a) lateral surface area andb) the volume.Round to the nearest hundredth. Use the pi button.

Answer 1

Given that the diameter of the cylinder i 1d = 9 inches and the height is 2h =1 inches.

The adisuswill be r, r = d/2

r = 19/2 inches

Now,

A). The lateral surface area of the cylinder is given as

`LSA=2\pi rh`

On puttingthe values we have

`\begin{gathered} LSA=2*(22)/(7)*(19)/(2)*21\text{ sq inches} \\ LSA=22*19*3\text{ sq inches} \\ LSA=1254\text{ sq inches} \end{gathered}`

Hence, the lateral surface area is 1254 sq inches.

B). The volume of the cylinder is

`Volume=\pi r^2h`

On putting the values we have

`\begin{gathered} V=(22)/(7)*(19)/(2)*(19)/(2)*21\text{ cubic inches} \\ V=(11*19*19*3)/(2)\text{ cubic inches} \\ V=5956.5\text{ cubic inches} \end{gathered}`

Hence, the volume will be 5956.5 cubc inches.