Question

9x + 10x - x4x2 - 7x + 8-x?+ 9x + 12What is the perimeter of the path?A 12x^2 + 2x + 20B.- x^3 + 13x^2 + 11x + 20C. 12x^2 + 25x + 20D.-x^3 + 15x^2 + 25x + 20

Answer 1

we know that

The perimeter of a triangle is equal to the sum of its three length sides

we have

9x+10x^2-x^3

4x^2-7x+8

-x^2+9x+12

so

Sum the three length sides

P=(9x+10x^2-x^3)+(4x^2-7x+8)+(-x^2+9x+12)

Group terms

P=(-x^3)+(10x^2+4x^2-x^2)+(9x-7x+9x)+(8+12)

Combine like terms

P=-x^3+13x^2+11x+20

therefore

OPtion B