Question

An atom of germanium-69 emits a positron.
Express your answer as a nuclear equation.

Answer 1

69/32Ge --> 0/+1 e + 69/31 Ga

Answer 2

The nuclear reaction is expressed as:

`_(32)^(69)\textrm{Ge}\rightarrow _(31)^(69)\textrm{Ga}+_(+1)^0e`

Step-by-step explanation:

Positron decay is a process which a proton gets converted into neutron and an electron neutrino and releases positron particles. This particle carries a charge of +1 units.

`_Z^A\textrm{X}\rightarrow _(Z-1)^A\textrm{Y}+_(+1)^0e`

An atom of germanium-69 emits a positron.

The nuclear reaction is expressed as:

`_(32)^(69)\textrm{Ge}\rightarrow _(31)^(69)\textrm{Ga}+_(+1)^0e`