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How many sets of three integers between 1 and 20 are possible if no two consecutive integers are to be in a set?

User Doraemon
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1 Answer

3 votes
I'm pretty sure that the solution looks like this
(20-3)!(20-4)!(20-5)!...(20-19)!. But Also you can use this formula (r-k+1 C r). You will get 18C3.
User Dan Doyon
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