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Find the area of the surface generated by revolving the curve x = (e^y + e^-y) / 2 from x = 0 to x = ln(2).

1 Answer

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Here's the calculation of area
π [ ln 2+ 1 / 2sinh(2 ln 2) ]=π [ln 2+1 4(2^22^−2) ]

=π [ln 2+1 / 4( 4− 1 / 4)]=π (ln 2+15 / 16) ≈ 5.122
User TaW
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