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PART1

Simplify completely: the quantity 5 times x to the third power plus 10 times x to the 2nd power plus 15 times x all over 5 times x

a.x^2 + 10x^2 + 15x

b.2x + 6

c.x^2 + 2x + 3

d.x^4 + 2x^3 + 3x^2



PART2
Simplify completely: the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x

a.the quantity 3 times x to the third power plus 5 times x plus 2 all over x

b.3x^3 + 5x + 2

c.3x^2 + 5x^2 + 2x

d.3x^5 + 5x^3 + 2x^2

2 Answers

3 votes

Answer: cccccc

Explanation:

User Rino
by
7.8k points
2 votes
P1. The answer is c.x^2 + 2x + 3

the quantity 5 times x to the third power plus 10 times x to the 2nd power plus 15 times x all over 5 times x is:
(5 x^(3)+10x^(2)+15x )/(5x)


(5 x^(3)+10x^(2)+15x )/(5x) =(5x* x^(2)+5x*2x+5x *3)/(5x)= (5x( x^(2) +2x+3))/(5x) = x^(2) +2x+3


P2. The answer is b.3x^3 + 5x + 2

the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x is:
(3 x^(4)+5 x^(2) +2x )/(x)


(3 x^(4)+5 x^(2) +2x )/(x) = (x*3 x^(3) +x*5x+x*2)/(x) = (x(3 x^(3) +5x+2))/(x) =3 x^(3) +5x+2
User Amiel Martin
by
8.3k points