Question

Simplify completely: the quantity 8 times x to the third power plus 6 times x to the 2nd power minus 4 times x all over negative 2 times x

a.−4x^2 − 3x + 2

b.−4x^2 + 3x + 2

c.4x^4 + 3x^3 − 2x^2

d.4x^2 + 6x^2 − 4x

Answer 1

Answer A

Explanation:

Answer 2

The answer is a.−4x^2 − 3x + 2

the quantity 8 times x to the third power plus 6 times x to the 2nd power minus 4 times x all over negative 2 times x is:
`(8 x^(3)+6 x^(2) -4x )/(-2x)`


`(8 x^(3)+6 x^(2) -4x )/(-2x) = -(8 x^(3)+6 x^(2) -4x )/(2x)=- (2x*4 x^(2) +2x*3x-2x*2)/(2x) =- (2x(4x^(2) +3x-2))/(2x) = \\ \\ =-(4x^(2) +3x-2)=-4x^(2) -3x+2`