2.40 g of NH4Cl is added to 19.4 g of water. Calculate the molality of the solution.

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asked Mar 28, 2017 15.2k views

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2.40 g of NH4Cl is added to 19.4 g of water. Calculate the molality of the solution.

Chemistry
high-school

Jhnclvr asked

by Jhnclvr

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Molality is the moles of solute per kg of solvent.

Moles of NH₄Cl = 2.4 / (14 + 4 x 1 + 35.5)
= 0.0448 mole

Molality = 0.0448 / (19.4 / 1000)
= 2.31 m

Nikhil Mohan answered Apr 4, 2017

by Nikhil Mohan

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