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How many liters of 18.5 molar HCl stock solution will be needed to make 25.0 liters of 1.5 molar HCl solution? Show the work used to solve this problem.

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1) Find the number of moles that the final solution must contain

M = n / liters of solution => n = M*liters of solution

n = 1.5 mol/liter * 25.0 liter = 37.5 moles

2) Find how many liters of the stock solution contain 37.5 moles of HCL

M = n / liters of sulution => liters of solution = n / M = 37.5 mol / 18.5 mol/liter

liter of solution = 2.03 liter

Answer: 2.03 liter
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