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determine the specific heat of a mayterial if a 35g sample of the material absorbs 48J as it is heated from 298K to 313K
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determine the specific heat of a mayterial if a 35g sample of the material absorbs 48J as it is heated from 298K to 313K

User DiogoSantana
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Data:

m = 35g
Q = 48 j
T1 = 298K
T2 = 313K
Cs = ?

Fórmula: Q = m*Cs*(T2 - T1) => Cs = Q / [m (T2 - T1)]

Cs = 48 j / [35g (313K - 298K] = 0.0914 j / g*K = 91.4 j / kg*K
User Aleksandr Belugin
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