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Write expression as a complex number in standard form and show work [(13i)/(1-2i)]

User Kellan
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the solution
let A = 13i /1-2i
so A = 13i (1+2i) /(1-2i) ( 1+2i) = 13i (1+2i) /1² - (2i)² = 13i -26 / 1
finally A = 13i -26
User Ricky Levi
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