Question

What are the coordinates of the vertex of the graph of the function y = –x² + 6x –11?

(3, –2)
(3, 16)
(–3, –29)
(–3, –20)

Answer 1

The answer is (3,-2) Use x=-b/2a to get the x value then substitute that number back into the equation to get y. x=-6/-2 = 3 -(3)^2+6(3)-11 =-2

Answer 2

A.
`(3,-2)`

Explanation:

We have been given a function formula
`y=-x^2+6x-11`. We are asked to find the coordinates of the vertex of the graph.

We know that the x-coordinate of an equation in form
`y=ax^2+bx+c` can be determined using formula
`(-b)/(2a)`.

We can see that value of b is 6 and value of a is -1.

`(-6)/(2(-1))`

`(-6)/(-2)`

`3`

Now, we will substitute
`x=3` in given formula to find y-coordinate.

`y=-(3)^2+6(3)-11`

`y=-9+18-11`

`y=-2`

Therefore, the coordinates of vertex of the given function are
`(3,-2)`.