1 Answer

Typoerrpr · Answer 1 · 2017-09-11T20:21:04+0000

case 1
let A=log2(0.5)4 = log(0.5)4 x log(0.5)4 = 4log(0.5) x 4log(0.5) =16 log(0.5 +0.5) = 16 log 1 =0 if it is a neperian logarithm

case 2
logn n = 1, if it is logarithm with n as a basis,
so A=log2(0.5)4 = 4log2(0.5) = - 4 log2(2) = -4 x1 = -4

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