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Log base 5 (3) - log base 5 (5x) = 2
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1 vote
Log base 5 (3) - log base 5 (5x) = 2

User Saif Ali Khan
by
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1 Answer

6 votes
The answer is 3/125


log_a(x) - log_a(y)=log_a( (x)/(y) ) \\ log_5(3) - log_5(5x) = log_5( (3)/(5x))


log_5( (3)/(5x))=2

Since
log_b(x)=y is
b^(y) =x, then:

log_5( (3)/(5x))=2 is

5^(2) = (3)/(5x) \\ 25 = (3)/(5x) \\ 5x*25=3 \\ 125x=3 \\ x=3/125
User Tedil
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