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If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

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4 votes

Answer:

-3/4

Step-by-step explanation: A P E X

User Daniel Sp
by
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4 votes

\sin\theta= (4)/(5) \\ \\\sin^2\theta+\cos^2\theta=1 \\ \cos\theta=\pm √(1-\sin^2\theta) =\pm \sqrt{1-( (4)/(5))^2 } =\pm \sqrt{1- (16)/(25) } =\pm \sqrt{(9)/(25) }=\pm (3)/(5)}


\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-(3)/(5)


\cot\theta= (\cos\theta)/(\sin\theta)= (-(3)/(5))/((4)/(5)) =- (3)/(4)

User Garrison
by
8.2k points

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