Question

Find the complex zeros of x^3+27. write f in factored form

Answer 1

`x^3+27=0 \\x^3+3^3=0 \\(x+3)(x^2-3x+9)=0 \\x^2-3x+9=0 \\a=1,b=-3,c=9 \\ \\x_(1,2)= (-b\pm √(b^2-4ac) )/(2a) = (-(-3)\pm √((-3)^2-4*1*9) )/(2*1) =(3\pm √(-27) )/(2) =(3\pm 3√(3)i )/(2) \\ \\(x+3)(x-(3+ 3√(3)i )/(2))(x-(3- 3√(3)i )/(2))=0`