Question

Find the perimeter of a rhombus having two consecutive vertices at (2, 5) and (-1, 3).

4square root of 5
4square root of 10
4square root of 13
4square root of 65

Answer 1

Correct answer is C.


`(2, 5) \text{ and } (-1, 3) \\x_1=2,y_1=5,x_2=-1,y_2=3 \\ \\d= √((x_2-x_1)^2+(y_2-y_1)^2)= √((-1-2)^2+(3-5)^2)= √(13) \\ \\P=4d \\P=4√(13)`