Question

Find the area of triangle ABC with the given parts. Round to the nearest whole number.

A = 26.4°
b = 12.3 in.
c = 7.7 in.

a- 19.1 in.2
b- 42.4 in.2
c- 44.4 in.2
d- 21.1 in.2

Answer 1

`sin(26.4^o)= (h)/(12.3) \\ \\h=12.3* sin(26.4^o)=5.47 \\ \\A= (7.7*5.47)/(2)= 21.06`