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How many grams of CIF3 form when .204 moles of F2 react with excess Cl2? The answer must be sold with dimensional analysis.
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How many grams of CIF3 form when .204 moles of F2 react with excess Cl2?

The answer must be sold with dimensional analysis.

User Dieter B
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1 Answer

4 votes
The reaction equation:
2Cl₂ + 3F₂ → 2ClF₃

Moles of F₂ = 0.204
Moles of ClF₃ = 2/3 x 0.204
= 0.136 mole

Mass = moles x Mr
= 0.136 x (35.5 + 19 x 3)
= 12.58 grams of ClF₃ will be formed.
User Kbrown
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