Question

16 g of CH4 react with 64 g of O2 producing 44 g of CO2 how many grams of water are produced?

Answer 1

By applying the law of conservation of mass to the stoichiometry of the reaction between methane and oxygen, it is calculated that 36 grams of water are produced when 16 g of methane react with 64 g of oxygen to yield 44 g of carbon dioxide.

Step-by-step explanation:

The chemical reaction between methane (CH4) and oxygen (O2) to produce carbon dioxide (CO2) and water (H2O) can be represented by the balanced equation:

CH4 + 2O2 → CO2 + 2H2O

From the conservation of mass and stoichiometry of the reaction, we can deduce that 16 g of methane react with 64 g of oxygen to produce 44 g of carbon dioxide and a certain amount of water. By subtracting the mass of carbon dioxide from the total mass of reactants, we can find the mass of water produced:

Mass of reactants (CH4 and O2) = 16 g + 64 g = 80 g
Mass of products (CO2 and H2O) = Mass of reactants
Mass of water = Mass of reactants - Mass of CO2
Mass of water = 80 g - 44 g = 36 g

Thus, 36 grams of water are produced from this reaction.

Answer 2

We can apply the law of conservation of mass here, so the total amount of substances before the reaction should be equal to the total amount after reaction.

Methane + Oxygen = Carbon dioxide + water
16 + 64 = 44 + water
Water = 36 grams