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ABCD is a rhombus with diagonals intersecting at E. If m

User Nadege
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*ABCD is a rhombus with diagonals intersecting at E. If m<ABC = 4m<BAD, find m<EBC.
Well, your question is a bit incomplete that makes it worse to give you exactly what you need. But, according to the fact that diagonals intersecting, all the angles =360 degrees.
Suppose
\ \textless \ BAD=x. and
\ \textless \ ABC=4x
which means that opposite ones are equal
so, the solution is :

2(x+4x)=360
or could be
10x= 360 x=36
So, we have : <BAD=36 and <ABC=144
And the answer is :
4m+m=180.
Do hope you will find it helpful!

User Minion
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