Differentiate the function g(x) = ln[x(sqrt(x^2 - 1))]

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asked May 13, 2017 65.0k views

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Ravan · Answer 1 · 2017-05-18T21:36:57+0000

g(x) = ln[x(sqrt(x^2 - 1))]
g'(x) = 1/[x(sqrt(x^2 - 1))] * (x^2/sqrt(x^2 - 1) + sqrt(x^2 - 1)) = ((x^2 + x^2 - 1)/sqrt(x^2 - 1)) / x(sqrt(x^2 - 1)) = (2x^2 - 1) / x(x^2 - 1) = (2x^2 - 1) / (x^3 - x)

Differentiate the function g(x) = ln[x(sqrt(x^2 - 1))]

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