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Find equation of circle tangent to 3x-4y-4=0 at (0,-1) containing the point (-1,-8)

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i think I'm pretty sure that the center is the perpendicular bisector of the line joining (0, -1) and (-1 , -8)
So the equation would be :
(x-2) ^2 + (y+5) ^2 = 25

Hope this helps
User Antony Thomas
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