Question

Consider the chemical equation CH4 + 2 O2 → CO2 + 2 H2O. In this equation, CH4 is a

A. product
B. reactant
C. displacement

Answer 1

`\huge \boxed{\mathrm{B. \ reactant}}`

`\rule[225]{225}{2}`

Step-by-step explanation:

`\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O`

Balancing the Hydrogen atoms on the right side,

`\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O`

Balancing the Oxygen atoms on the left side,

`\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O`

Reactants are on the left side:

`\sf \boxed{\sf CH_4 + O_2} \Rightarrow CO_2 + H_2O`

`\rule[225]{225}{2}`

Answer 2

`CH4+2O2=\ \textgreater \ CO2+2H2O`
Since terms which are placed left to the arrow mark are reactants and those placed right are products you can easily solve the task represented above. According to the information I've provided CH4 is reactant and it is Fule. So, the correct answer is B.