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Sheryl's mean average on eight exams is 83.750. Find the sum of her scores. A. 770 B. 670 C. 693 D. 686
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Sheryl's mean average on eight exams is 83.750. Find the sum of her scores.

A. 770

B. 670

C. 693

D. 686

User NealR
by
7.7k points

1 Answer

2 votes
The answer is B. 670

The mean average (X) is sum (s) of the values divided by the number of values n:
X = s / n

X = 83.750
n = 8
s = ?

s = X * n
s = 83.750 * 8 = 670
User Arman Feyzi
by
8.6k points
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