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How many 6 digit odd numbers are possible if the leftmost digit cannot be zero?
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How many 6 digit odd numbers are possible if the leftmost digit cannot be zero?

User Artem Zelinskiy
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3 votes
the correct answer is 9 x 5 x 10 = 450
User Aswin Mohan
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9.0k points
4 votes
There are 9 choices for the first digit: 1,2,3,4,5,6,7,8,9
There are 10 choices for the second digit: 0,1,2,3,4,5,6,7,8,9
There are 5 choices for the third digit: 1,3,5,7,9

That's 9×10×5 = 450
User Kevlar
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