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What are the dimensions of a rectangular box with a volume of 50b3 - 3 - 2b + 75b2?

(2b + 3); (5b - 1); (5b - 1)
(2b + 3); (5b + 1); (5b - 1)
(2b - 3); (5b - 1); (5b + 1)

2 Answers

5 votes

Answer:

The answer is B.

Step-by-step explanation: Because I got it right.

User Janek Olszak
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So the formula for getting the volume of a rectangular box is V= lxwxh.
Given the volume above, the dimensions of the box would be: (2b + 3); (5b + 1); (5b - 1) So when you multiply these given dimensions, the result would be 50b3+75b2-2b-3. I hope that this is the answer that you are looking for.
User McKabue
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