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Multiply. State any excluded values.

q+5/-3 * -3q/q+2

User Traffy
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1 Answer

3 votes
The given equation is:


(q+5)/(-3) * (-3q)/(q+2)

Just multiply both numerators and both denominators respectively, with the bar line still between them. So, it becomes


((q+5)(-3q))/((-3)(q+2)) = (-3 q^(2)-15q )/(-3q-6)

Then you factor out the equations:


(-3 q^(2)-15q )/(-3q-6) = (-3q(q+5))/(-3(q+2))

Simplify terms by dividing them. The negative sign and 3 cancels out. The answer would be:


(q(q+5))/((q+2))


User DDave
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