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For the reaction, NH3(g) + HCl(g) NH4Cl(s) run at 25°C, ΔG = −91368 J and ΔS = −284 J/K. What is the enthalpy change for this reaction?

184,632 J

−91,084 J

−98,468 J

−176,000 J


TRUE or FALSE. A negative change in free energy, or −ΔG, represents a spontaneous reaction.

User WiseGuyEh
by
8.4k points

2 Answers

3 votes

Answer:

For 1: The enthalpy change for the given reaction is -176000 J.

For 2: Yes, the negative sign of the gibbs free energy represents a spontaneous reaction.

Step-by-step explanation:

  • For 1:

For the given chemical reaction:


NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)

We are given:


\Delta G = Gibbs free energy = -91368 J

T = Temperature =
25^oC=[273+25]K=298K


\Delta S = entropy of the reaction = -284 J/K

To calculate the enthalpy of the reaction, we use the equation for gibbs free energy, which is:


\Delta G=\Delta H-T\Delta S

Putting values in above equation, we get:


-91368J=\Delta H-(298K)(-284J/K)\\\\\Delta H=-176000J

Hence, the enthalpy change for the given reaction is -176000 J.

  • For 2:

Gibbs free energy is defined as the energy which is available to do some work. It is represented as
\Delta G

Sign convention for
\Delta G

  • If
    \Delta G value comes out to be positive, it is considered as non-spontaneous reaction.
  • If
    Delta G value comes out to be negative, it is considered as spontaneous reaction.

So, yes the negative sign of the gibbs free energy represents a spontaneous reaction.

User Nstosic
by
8.6k points
5 votes
For question 1:

25°C = 298 K
ΔG = ΔH - T ΔS
ΔH= ΔG + TΔS = −91368 + (298)(−284)=−91368-84632=-175730
Therefore ΔH is approx - 176,000 J

For question 2:

The statement "A negative change in free energy, or −ΔG, represents a spontaneous reaction." is false
User Manthan Tilva
by
8.1k points
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