How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?

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asked Sep 18, 2017 94.7k views

1 Answer

Vladimir Dyuzhev · Answer 1 · 2017-09-24T19:22:48+0000

The solution for the question above is:

C = 0.270
V = 0.0275L
n = ?

Use the molar formula which is: C = n/V
Re-arrange it to: n = CV
n = (0.270)*(0.0275)
n = 0.007425 mols
(more precise) n = 7.425 x 10^-3 mols

7.425 x 10^-3 mols is the answer.

How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?

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